Moldovan tennis player Radu Albot qualified for the quarterfinals of the ATP 250 tournament “Delray Beach Open” that is held in Florida, IPN reports.
He beat Australia’s Nick Kyrgios, World No. 64, 6-2, 3-6, 6-3. In the quarterfinals, Albot plays against the United States’ Steve Johnson, World No. 34.
Also tomorrow, February 23, Radu Albot competes in the doubles semifinals. He and Yoshihito Nishioka of Japan meet brothers Ken and Neal Skupski of the UK.
Вы используете модуль ADS Blocker .
IPN поддерживается от рекламы.
Поддержи свободную прессу!
Некоторые функции могут быть заблокированы, отключите модуль ADS Blocker .
Спасибо за понимание!
Команда IPN.
