The national women’s tennis team of Moldova managed to qualify for the playoff round of the Fed Cup 2016. Moldova beat Cyprus 2-1 in the last match of the group, IPN reports.

In the first Moldovan-Cypriot duel, Adriana Sosnovschi beat Maria Shiopacha 6-1, 6-3 after a struggle of 1 hour and 30 minutes. Afterward, Moldova’s top player Daniela Ciobanu was defeated by Eliza Omirou 6-7, 6-4 and 3-6 in a match that lasted for almost 3 hours. The winner was decided in the doubles, where the pair Adriana Sosnovschi - Vitalia Stamat won against Eliza Omirou - Maria Siopacha 6-4, 7-6.

On April 16, Moldova meets Luxemburg. The winner will qualify for the Fed Cup Europe/Africa Zone Group II.